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Stack Columns of Data on one column

December 23rd, 2005 Leave a comment Go to comments

I have modified this code for better explanation and error handling (includes a function to check if a worksheet exists or not). To run this code follow these steps:
1. Insert a new module in your workbook,
2. Copy and paste this code,
3. Go back to worksheet with data in it,
4. Press Alt + F8 to bring the macro window
5. Select this procedure and hit run
6. Enter the new worksheet name in the input box
7. If everything went well, you should have a new worksheet with all the data from original worksheet in one column with the column headers. See the screen shots for example.
Before stacking-the original data:
Before Stack
After stacking:
After Stack
Here’s the code:

Option Explicit
 
Sub Stack_cols()
 
On Error GoTo Stack_cols_Error
 
Dim lNoofRows As Long, lNoofCols As Long
Dim lLoopCounter As Long, lCountRows As Long
Dim sNewShtName As String
Dim shtOrg As Worksheet, shtNew As Worksheet
 
'Turn off the screen update to make macro run faster
Application.ScreenUpdating = False
'Ask for a new sheet name, if not provided use newsht
sNewShtName = InputBox("Enter the new worksheet name", "Enter name", "newsht")
'Set a sheet variable for the sheet where the data resides
Set shtOrg = ActiveSheet
'Add a new worksheet, rename it and set it to a variable
If Not SheetExists(sNewShtName) Then
Worksheets.Add(After:=Worksheets(Worksheets.Count)).Name = sNewShtName
Set shtNew = Worksheets(sNewShtName)
Else
MsgBox "Worksheet name exists. Try again", vbInformation, "Sheet Exists"
Exit Sub
End If
 
With shtOrg
'Get the last column number
'Replace .Range("IV1") with .Range("XFD1") for Excel 2007
lNoofCols = .Range("IV1").End(xlToLeft).Column
'Start a loop to copy and paste data from the first column to the last column
For lLoopCounter = 1 To lNoofCols
'Count the number of rows in the looping column
'Replace .Cells(65536, lLoopCounter) with .Cells(1048576, lLoopCounter) for Excel 2007
lNoofRows = .Cells(65536, lLoopCounter).End(xlUp).Row
.Range(.Cells(1, lLoopCounter), .Cells(lNoofRows, lLoopCounter)).Copy Destination:=shtNew.Range(shtNew.Cells(lCountRows + 1, 1), shtNew.Cells(lCountRows + lNoofRows, 1))
'count the number of rows in the new worksheet
lCountRows = lCountRows + lNoofRows
Next lLoopCounter
End With
 
On Error GoTo 0
SmoothExit_Stack_cols:
Application.ScreenUpdating = True
Exit Sub
 
Stack_cols_Error:
MsgBox "Error " & Err.Number & " (" & Err.Description & ") in Sub:Stack_cols"
Resume SmoothExit_Stack_cols
End Sub
'Check if a worksheet exists or not
Public Function SheetExists(sShtName As String) As Boolean
On Error Resume Next
 
Dim wsSheet As Worksheet, bResult As Boolean
bResult = False
Set wsSheet = Sheets(sShtName)
 
On Error GoTo 0
If Not wsSheet Is Nothing Then
bResult = True
End If
SheetExists = bResult
End Function
  1. Anonymous
    June 8th, 2007 at 16:10 | #1

    did the trick, thanks you genius! JAmes UK)

  2. EfficienC
    August 27th, 2007 at 18:09 | #2

    could you perhaps show me how to implement your code? I’m having trouble getting results when running it. Thanks!

  3. Ashutosh
    August 29th, 2007 at 12:47 | #3

    EfficienC:
    I’ve modified the code. I hope that this offers more explanation.

  4. Anonymous
    September 27th, 2007 at 03:55 | #4

    Works PERFECTLY!!!! This just save me HOURS and HOURS of manual work. Thank you! – dub3

  5. Edward
    February 6th, 2008 at 08:42 | #5

    Any chance this can be translated for Excel 2007? This seems like exactly the thing to save tons of time in excel.

    Thanks

    Edward

  6. Ashutosh
    February 6th, 2008 at 13:22 | #6

    Edward,

    I’ve modified the code, and put two comments:
    ‘Replace .Range(“IV1″) with .Range(“XFD1″) for Excel 2007
    lNoofCols = .Range(“IV1″).End(xlToLeft).Column

    ‘Replace .Cells(65536, lLoopCounter) with .Cells(1048576, lLoopCounter) for Excel 2007
    lNoofRows = .Cells(65536, lLoopCounter).End(xlUp).Row

    You have to make two changes to make this work for 2007. First, change the last column from IV to XFD. Second, change the number of rows from 65536 to 1048576.

  7. Anonymous
    May 1st, 2008 at 16:29 | #7

    Much Appreciated!

  8. Anonymous
    June 18th, 2008 at 14:53 | #8

    In order for this to be even more effective, you could stack into two columns, with the first column repeating the header information for each stacked column. E.g.
    A 1
    A 2
    A 3
    B 1
    B 2
    B 3

  9. Tina
    July 7th, 2008 at 18:20 | #9

    Thanks!
    Does anyone know how to unstack a column? Say I have similar categories of information for 9 groups of 11 cells, all stacked in one column. I am looking to create a table (9×11)… I would very much appreciate your insights!

  10. Anonymous
    August 31st, 2008 at 22:30 | #10

    thankyou so much…saved me a whole lot of work :)

  11. dmiech
    November 18th, 2008 at 14:36 | #11

    This is close to what I am looking for. How can I stack groups of columns? Like G groups of C columns? Or 10 Groups of 3 columns stacked in one group of 3 columns? It needs to be variable, because sometimes it might be 25 groups of 4 columns, etc. I can send an example of the data I have and how I need it to be arrange.

    Dan
    dmiech@aol.com

  12. darhay
    July 10th, 2009 at 09:56 | #12

    EXCELLENT. WORKED VERY WELL.
    (took me a while, i’m not used to Macros, but I realized that when you copy this code, the ” and the ‘ don’t copy correctly. So make sure you replace those)

  13. a7n9
    July 10th, 2009 at 10:22 | #13

    @darhay,
    I’m glad that it worked for you, darhay. I’m sorry that the quotes come out wrong. Those single quotes got messed up when I transferred my posts from blogger to wordpress. I will see if I can replace them correctly.

  14. jbl
    August 18th, 2009 at 15:12 | #14

    that was so easy!!!!
    thank you so much for putting this on the web.

  15. October 19th, 2009 at 06:05 | #15

    Absolutely brilliant.

  16. Dink
    July 15th, 2010 at 10:28 | #16

    Thanks….saved me loads of time.

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